16m^2-916m=0

Solution for 16m^2-916m=0 equation:

16m^2-916m=0

a = 16; b = -916; c = 0;
Δ = b2-4ac
Δ = -9162-4·16·0
Δ = 839056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{839056}=916$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-916)-916}{2*16}=\frac{0}{32}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-916)+916}{2*16}=\frac{1832}{32}
=57+1/4
$